Electric Field and the Gradient
of the Potential (see page 716 in Serway):
Potential is a scalar. Equipotential
lines, for example, represent the voltages at different points. Until now,
we have considered only field lines and equipotentials in a plane (consider
the equipotentials found in lab using the cupric acetate solution). The
basic relation is

How can we turn this relationship
around - obtain the field as a function of V? We need a new operator. Since
the magnitude of the field caused by a one-dimensional potential
is given by

we write 
where the vector operator "del"
is given by

(The vector arrow is not usually
written over "del", by custom, although it is a vector
operator.)
Here's the example, finally...
Problem: Suppose the potential
is given by
Find the Electric field.
Solution: We use the operator;
i.e., we take the gradient of the potential. Note that this is NOT a dot
or a cross product, since V is not a vector. "del" is an operator...

At the origin (0,0,0), the field
is undefined because of the z-coordinate in the denominator. At point (0,0,1)
the field is

To choose one more point as
a demonstration, the field at (1,0,1) is
